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楼主
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发表于 2019-8-23 09:32:54
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我这里分享关于直流电机控制的代码,希望能够 帮到同学们,大家可以进行借鉴
LIBRARY IEEE;
USE IEEE.STD_LOGIC_1164.ALL;
USE IEEE.STD_LOGIC_Arith.ALL;
USE IEEE.STD_LOGIC_Unsigned.ALL;
ENTITY moto IS
PORT(
clock: IN STD_LOGIC;
key: IN STD_LOGIC_VECTOR(2 DOWNTO 0);--按键输入(key1~key3)
pwm_in: IN STD_LOGIC; --产生的PWM波输入
pwm_en: OUT STD_LOGIC; --PWM控制使能端
duty_cycle: OUT STD_LOGIC_VECTOR(3 DOWNTO 0);--PWM占空比控制输出
motoa,motob:OUT STD_LOGIC; --PWM波输出
led: OUT STD_LOGIC_VECTOR(4 DOWNTO 0)
);
END;
ARCHITECTURE one OF moto IS
SIGNAL duty_cycle_io: STD_LOGIC_VECTOR(3 DOWNTO 0);
SIGNAL pwm_en_io: STD_LOGIC;
SIGNAL count: STD_LOGIC_VECTOR(16 DOWNTO 0);--时钟分频计数器
SIGNAL dout1,dout2,dout3:STD_LOGIC_VECTOR(2 DOWNTO 0);--消抖寄存器
SIGNAL moto_dir: STD_LOGIC;--电机正反转
SIGNAL k_debounce: STD_LOGIC_VECTOR(2 DOWNTO 0);--按键消抖输出
SIGNAL clk: STD_LOGIC;--分频时钟
SIGNAL key_edge: STD_LOGIC_VECTOR(2 DOWNTO 0);
BEGIN
led<=NOT (pwm_en_io & duty_cycle_io);--LED输出状态指示
pwm_en <= pwm_en_io;
duty_cycle <= duty_cycle_io;
PROCESS(clock)
BEGIN
IF RISING_EDGE(clock) THEN
IF count<120000 THEN
count<=count+1;
clk<='0';
ELSE
count<=B"0_0000_0000_0000_0000";
clk<='1';
END IF;
END IF;
END PROCESS;
-------------------------------------------<<按键消抖部分
PROCESS (clock)
BEGIN
IF RISING_EDGE(clock) THEN
IF clk='1' THEN
dout1<=key;
dout2<=dout1;
dout3<=dout2;
END IF;
END IF;
END PROCESS;
PROCESS (clock)
BEGIN
IF RISING_EDGE(clock) THEN
k_debounce<=dout1 OR dout2 OR dout3;--按键消抖输出.
END IF;
END PROCESS;
key_edge<=NOT (dout1 OR dout2 OR dout3) AND k_debounce;
PROCESS(clock)--按键1 控制电动机速度
BEGIN
IF RISING_EDGE(clock) THEN
IF key_edge(0)='1' THEN
duty_cycle_io<=duty_cycle_io+1;
END IF;
END IF;
END PROCESS;
PROCESS(clock)--按键2,控制电动机启动、停止
BEGIN
IF RISING_EDGE(clock) THEN
IF key_edge(1)='1' THEN
pwm_en_io<=NOT pwm_en_io;
END IF;
END IF;
END PROCESS;
PROCESS(clock)--按键3,控制电动机正/反转
BEGIN
IF RISING_EDGE(clock) THEN
IF key_edge(2)='1' THEN
moto_dir <=NOT moto_dir;
END IF;
END IF;
END PROCESS;
motoa<=pwm_in WHEN moto_dir='1' ELSE '0';
motob<='0' WHEN moto_dir='1' ELSE pwm_in;
END;
由于本人急需赫兹币,希望能够求得同学们的打赏,拜托了!
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